3[x+2]-2[x+1]=8

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Solution for 3[x+2]-2[x+1]=8 equation:


Simplifying
3[x + 2] + -2[x + 1] = 8

Reorder the terms:
3[2 + x] + -2[x + 1] = 8
[2 * 3 + x * 3] + -2[x + 1] = 8
[6 + 3x] + -2[x + 1] = 8

Reorder the terms:
6 + 3x + -2[1 + x] = 8
6 + 3x + [1 * -2 + x * -2] = 8
6 + 3x + [-2 + -2x] = 8

Reorder the terms:
6 + -2 + 3x + -2x = 8

Combine like terms: 6 + -2 = 4
4 + 3x + -2x = 8

Combine like terms: 3x + -2x = 1x
4 + 1x = 8

Solving
4 + 1x = 8

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + 1x = 8 + -4

Combine like terms: 4 + -4 = 0
0 + 1x = 8 + -4
1x = 8 + -4

Combine like terms: 8 + -4 = 4
1x = 4

Divide each side by '1'.
x = 4

Simplifying
x = 4

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